The factorisatian of 8 x 3 - 1 - 8 x 3 - 3 - 2 x - 6 x is-

The correct option is C #160;( 2 x + 1 / 2 x ) ( 2 x + 1 / 2 x ) ( 2 x + 1 / 2 x ) 8x^3+18x^3+32x+6x =(2x)^3+(12x)^3+3(12x+2x) =(2x)^3+( ...

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Algebraic Identities

The factorisa...

Question

The factorisatian of $8 x^{3} + \frac{1}{8 x^{3}} + \frac{3}{2 x} + 6 x$ is?

x (8 x^{2} + \frac{1}{8 x^{2}} + \frac{3 x}{2} + 6)

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x (8 x^{2} + \frac{1}{8 x^{4}} + \frac{3 x}{2} + 6)

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(2 x + \frac{1}{2 x}) (2 x + \frac{1}{2 x}) (2 x + \frac{1}{2 x})

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(2 x + \frac{1}{2 x})

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\frac{x + 2}{(x + 1) (2 x + 3)} - \frac{2 x + 3}{(x + 1) (x + 2)} + \frac{3 x + 5}{(2 x + 3) (x + 2)}

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y = s e c^{- 1} [\frac{x + 1}{x - 1}] + s i n^{- 1} [\frac{x - 1}{x + 1}]

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