Question

The factorisation of $2a^2+7a+6$ is

• A. $(a+2)(2a-3)$
• B. $(a-2)(2a+3)$
• C. $(a-2)(2a-3)$
• D. $(a+2)(2a+3)$

Answer 1

The correct option is D $(a+2)(2a+3)$

The given expression is
$2a^2+7a+6$
The product of first and last term is $12a^2$
The middle term is 7a
So, two terms whose product is $12a^2$ and sum is $7a$ will be
4a and 3a
So, splitting the middle term we get
= $2a^2+4a+3a+6$
= $2a(a+2)+3(a+2)$
= $(a+2)(2a+3)$ [Taking (a+2) common]