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Question

The factorisation of 2a - xa- 4b + 2bx is

A
(a +2b)(2- x)
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B
(a -2b)(2 + x)
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C
(a -2b)(2- x)
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D
(a + 2b)(2 + x)
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Solution

The correct option is C (a -2b)(2- x)
The given expression is
2a - xa - 4b + 2bx
Rearranging and grouping them we get
2a - 4b - xa + 2bx
= 2(a - 2b) - x (a - 2b) [Taking '2' and 'x' common]
= (a -2b)(2- x) [Taking (a - 2b) common]




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