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B
2y(y−3)(y−8)
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C
2y(y−3)(y+8)
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Solution
The correct option is B2y(y−3)(y−8) 2y3+10y2−48y
on taking ′2y′common from all the terms; =2y(y2+5y−24)
Now, using the method of middle term splitting; =2y(y2+8y−3y−24) =2y[y(y+8)−3(y+8)] =2y(y−3)(y+8)