The factorisation of $8 - a^{3} b^{3}$ is equal to .

(2 - a b) (4 + 2 a b + a^{2} b^{2})

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(2 - a b) (4 - 2 a b + a^{2} b^{2})

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(2 + a b) (4 + 2 a b + a^{2} b^{2})

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(2 + a b) (4 - 2 a b + a^{2} b^{2})

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Solution

The correct option is A $(2 - a b) (4 + 2 a b + a^{2} b^{2})$
The given expression is $8 - a^{3} b^{3}$
This can be written as
$2^{3} - (a b)^{3}$
= $(2 - a b) (2^{2} + 2 a b + a^{2} b^{2})$ ...[ $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ ]
= $(2 - a b) (4 + 2 a b + a^{2} b^{2})$

Suggest Corrections

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