The factorisation of the 1-2 a -3 a 2 is equal toA- 1-a1-3 aB- 1-a1-3 aC- 1-a1-3 aD- 1-a1-3 a

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Factorisation by Regrouping Terms

The factorisa...

Question

The factorisation of the $1 - 2 a - 3 a^{2}$ is equal to.

(1+a)(1- 3a)

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(1+a)(1+ 3a)

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(1-a)(1- 3a)

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(1-a)(1+ 3a)

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Solution

The correct option is A (1+a)(1- 3a)
The given expression is $1 - 2 a - 3 a^{2}$
The product of the first and last term is $- 3 a^{2}$
The middle term has to be split in such a way that the difference is -2a and product is $- 3 a^{2}$
The terms will be -3a and a as (-3a) (a) = $- 3 a^{2}$ and -3a + a = -2a
Spliting the middle term we get,
$1 + a - 3 a - 3 a^{2}$
= 1(1+a) - 3a(1+a) [Taking '3a' common]
= (1+a)(1- 3a)

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The factorisation of the 1−2a−3a2 is equal to.

The factorisation of the $1 - 2 a - 3 a^{2}$ is equal to.