The factors of 2 x 3-6 x 2-3 x -9 are-A- 2 x2-3B- x2-6- x -3D- 2 x 2

The correct options are A 2x^2+3 C x+3The given expression is 2 x^3+6 x^2+3x+9 nbsp; = 2 x^2(x+3) + 3(x+3) =(x+3)(2 x^2+3) Thus, (x+3) and (2 x^2 +3) are ...

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Byju's Answer

Standard VIII

Mathematics

Factorization of a Quadratic Trinomial

The factors o...

Question

The factors of $2 x^{3} + 6 x^{2} + 3 x + 9$ are:

2 x^{2} + 3

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x^{2} + 6

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x + 3

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2 x^{2}

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Solution

The correct options are
A $2 x^{2} + 3$
C $x + 3$
The given expression is

$2 x^{3} + 6 x^{2} + 3 x + 9 = 2 x^{2} (x + 3) + 3 (x + 3) = (x + 3) (2 x^{2} + 3)$

Thus, $(x + 3)$ and $(2 x^{2} + 3)$ are the two factors.

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Similar questions

Q. Evaluate the following:

\begin{matrix} {lim}_{x \to 1} \frac{x^{2} - 3 x + 2}{x^{2} - 4 x + 3} {lim}_{x \to 2} \frac{x^{3} + x^{2} - 12}{x^{3} - x^{2} - x - 2} {lim}_{x \to \sqrt{2}} \frac{x^{2} + x \sqrt{2} - 4}{x^{2} - 3 x \sqrt{2} + 4} {lim}_{x \to 3} \frac{x^{3} - 3 x^{2} - x + 3}{x^{3} - 6 x^{2} + 9 x} \end{matrix}

The roots of quadratic equation are 2x²+3x-9 = 0 are:

Find f o g when f (x) = 2 x + 1

and

g (x) = x^{2} - 2

Find the quotient when polynomial $2 x^{3} + 6 x^{2} + 7 x + 60$ is divide by $2 x^{2} - 2 x + 15$

Find the factors of $6 x^{2} - 13 x + 6 = 0$

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The factors of 2 x3+6 x2+3x+9 are:

The correct options are A 2x2+3 C x+3The given expression is 2 x3+6 x2+3x+9=2 x2(x+3)+3(x+3)=(x+3)(2 x2+3) Thus, (x+3) and (2 x2+3) are the two factors.

The factors of $2 x^{3} + 6 x^{2} + 3 x + 9$ are:

The correct options are
A $2 x^{2} + 3$
C $x + 3$
The given expression is

$2 x^{3} + 6 x^{2} + 3 x + 9 = 2 x^{2} (x + 3) + 3 (x + 3) = (x + 3) (2 x^{2} + 3)$

Thus, $(x + 3)$ and $(2 x^{2} + 3)$ are the two factors.