The factors of $2 x^{2} - 3 x - 2$ are

(2 x - 1) (x + 2)

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(2 x + 1) (x - 2)

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(x + 1) (x - 2)

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(x - 1) (x + 2)

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Solution

The correct option is D $(2 x + 1) (x - 2)$
Given, $2 x^{2} - 3 x - 2 = 2 x^{2} - 4 x + x - 2$
$= 2 x (x - 2) + 1 (x - 2)$
$= (2 x + 1) (x - 2)$
Option B is correct.

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Similar questions

2 x^{2} + 7 x + 6

\frac{1}{(x - 1) (x - 2)} + \frac{1}{(x - 2) (x - 3)} + \frac{1}{(x - 3) (x - 4)} = \frac{1}{6}

Which of the following are the factors of $x^{2} + 3 x + 2$ ?

\sqrt{2} x^{2} + 3 x + \sqrt{2} =

(\sqrt{2} x + 1) (x + \sqrt{2})

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