The factors of $(4 x^{3} + 12 x^{2} + 6 x + 18)$ is/are:

$2 x^{2} + 5$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$4 x^{2} + 6$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$(x + 3)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$None of these$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$(x + 3)$

$4 x^{3} + 12 x^{2} + 6 x + 18 = 4 x^{2} (x + 3) + 6 (x + 3) = (x + 3) (4 x^{2} + 6)$

Thus, $(x + 3)$ and $(4 x^{2} + 6)$ are the two factors.

Suggest Corrections

Similar questions

The factors of $(4 x^{3} + 12 x^{2} + 6 x + 18)$ is/are:

Question :

One of the factors of x⁵+x+1 is

(1) 2x² - x - 1

(2) x³ - x²+ 1

(3) x² - 2x² + 1

(4) x³ + x² + 1

x^{3} + 9 x^{2} - 6 x - 4

27 - 6 x - x^{2}

Join BYJU'S Learning Program