The factors of (4 x3+12 x2+6x+18) is/are:
2x2+5
4x2+6
3x3+2
None of these
4 x3+12 x2+6x+18=4 x2(x+3)+6(x+3)=(x+3)(4 x2+6)
Thus, (x+3) and (4 x2+6) are the two factors.
The factors of 4x3+12x2+6x+18 are:
Which of the following is/are the factor(s) of 4x3+12x2+5x+15?