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Question

The factors of 625a1281b12 are:

A
(25a6+9b6)(5a33b3)(5a3+3b3)
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B
(5a3+3b3)2(5a33b3)2
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C
(5a33b3)4
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D
(25a69b6)2
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Solution

The correct option is A (25a6+9b6)(5a33b3)(5a3+3b3)
625a128b12
=(25a6)2(9b6)2=(25a69b6)(25a6+9b6)
=[(5a3)2(3b3)2](25a6+9b6)
=(5a33b3)(5a3+3b3)(25a6+9b6)

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