wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The factors of 6x2−x−15 are (2x+3) and _____

A
(3x5)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(3x+5)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(5x3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(2x3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C (3x5)
6x2x15
=6x210x+9x15
=2x(3x5)+3(3x5)
=(2x+3)(3x5)
Then other factor is (3x5)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Remainder Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon