The factors of a2 - 1-a2 are

The correct option is C ( a 1/a ) (a + 1/a ) Formula used: (a+b)(a b)=a^2 b^2 a^2 1/a^2=(a)^2 (1/a)^2 nbsp; nbsp; nbsp; nbsp; nbs ...

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Expansion of (x^2 - y^2)

The factors o...

Question

The factors of $a^{2} - \frac{1}{a^{2}}$ are

(a + \frac{1}{a}) (a + \frac{1}{a})

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(a - \frac{1}{a}) (a - \frac{1}{a})

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(a - \frac{1}{a}) (a + \frac{1}{a})

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None of these

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Solution

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f (x) = [\frac{a + x}{1 + x}]^{a + 1 + 2 x}

a^{a + 1} [2 l o g a + \frac{1 - a^{2}}{a}]

lim n \to \infty n \sum a = 2 {sin}^{- 1} [\frac{\sqrt{(a^{2} + 2 a)} - \sqrt{(a - 1) (a + 1)}}{a (a + 1)}] = \frac{k π}{120},

k

A = [\begin{matrix} a & b \\ c & \frac{1 + b c}{a} \end{matrix}]

a A^{- 1} = (a^{2} + b c + 1) I - a A .

[A (A + B)^{- 1} B]^{- 1} = B^{- 1} + A^{- 1}

[A (A + B)^{- 1} B]^{- 1} = [A (A^{- 1} + B^{- 1}) B]^{- 1} = [(I + A B^{- 1}) B]^{- 1} = [(B + A B^{- 1} B)]^{- 1} = [(B + A I)]^{- 1} = [(B + 1)]^{- 1} = B^{- 1} + A^{- 1}

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