The factors of -3x2 - 11x - 6-3 are

The correct option is D (x + 3√(3)) (√(3)x + 2) #160; √( 3 ) x^ 2 + 11x + 6√( 3 ) =√( 3 ) x^ 2 +9x+2x+ 6√( 3 ) =√( 3 ) x( x+ 3 ...

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Byju's Answer

Standard IX

Mathematics

Factorization of Expressions Reducible to Difference of Two Squares

The factors o...

Question

The factors of $\sqrt{3} x^{2} + 11 x + 6 \sqrt{3}$ are

(x - 3 \sqrt{3}) (\sqrt{3} x + 2)

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(x - 3 \sqrt{3}) (\sqrt{3} x - 2)

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(x + 3 \sqrt{3}) (\sqrt{3} x - 2)

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(x + 3 \sqrt{3}) (\sqrt{3} x + 2)

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Solution

The correct option is D $(x + 3 \sqrt{3}) (\sqrt{3} x + 2)$
$\sqrt{3} x^{2} + 11 x + 6 \sqrt{3} = \sqrt{3} x^{2} + 9 x + 2 x + 6 \sqrt{3} = \sqrt{3} x (x + 3 \sqrt{3}) + 2 (x + 3 \sqrt{3}) = (x + 3 \sqrt{3}) (\sqrt{3} x + 2)$ .

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Similar questions

Question 24
Factorise
(i) $2 x^{3} - 3 x^{2} - 17 x + 30$

(ii) $x^{3} - 6 x^{2} + 11 x - 6$

(iii) $x^{3} + x^{2} - 4 x - 4$

(iv) $3 x^{3} - x^{2} - 3 x + 1$

Q. Factorize:

(i)

x^{3} + 3 x^{2} + 3 x - 7

(ii)

x^{3} - 3 x^{2} + 3 x + 7

[4 MARKS]

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Factorize

x^{3} + 3 x^{2} - x - 3

Q. If

f (x) = 2 x^{3} + 3 x^{2} - 11 x + 6

, find

f (- 3)

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The factors of √3x2+11x+6√3 are

The correct option is D (x+3√3)(√3x+2)√3x2+11x+6√3=√3x2+9x+2x+6√3=√3x(x+3√3)+2(x+3√3)=(x+3√3)(√3x+2).

The factors of $\sqrt{3} x^{2} + 11 x + 6 \sqrt{3}$ are

The correct option is D $(x + 3 \sqrt{3}) (\sqrt{3} x + 2)$
$\sqrt{3} x^{2} + 11 x + 6 \sqrt{3} = \sqrt{3} x^{2} + 9 x + 2 x + 6 \sqrt{3} = \sqrt{3} x (x + 3 \sqrt{3}) + 2 (x + 3 \sqrt{3}) = (x + 3 \sqrt{3}) (\sqrt{3} x + 2)$ .