The factors of t2-6 t-9 are

The correct option is B (t + 3)(t + 3) The given expression is t2 + 6t + 9 = t2 + 2(3)t + 32 nbsp; Using nbsp;[(a+b)^2 = a^2+ b^2+2ab] t2 + 2(3)t + 32 ...

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Standard VIII

Mathematics

Factorization of a Quadratic Trinomial

The factors o...

Question

The factors of t² + 6t + 9 are __________.

(t + 3)(t - 3)

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(t + 3)

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(t - 3)(t - 3)

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(t + 3)(t + 3)

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Solution

The correct option is D
(t + 3)(t + 3)

The given expression is

t² + 6t + 9

= t² + 2(3)t + 3²

Using $[(a + b)^{2} = a^{2} + b^{2} + 2 a b]$

t² + 2(3)t + 3² = (t + 3)²
= (t + 3)(t + 3)

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The factors of t2 + 6t + 9 are __________.

The correct option is D (t + 3)(t + 3) The given expression is t2 + 6t + 9 = t2 + 2(3)t + 32 Using [(a+b)2=a2+b2+2ab] t2 + 2(3)t + 32 = (t + 3)2 = (t + 3)(t + 3)

The factors of t² + 6t + 9 are __________.

The correct option is D
(t + 3)(t + 3)

The given expression is

t² + 6t + 9

= t² + 2(3)t + 3²

Using $[(a + b)^{2} = a^{2} + b^{2} + 2 a b]$

t² + 2(3)t + 3² = (t + 3)²
= (t + 3)(t + 3)