The factors of the polynomial equation P(x) = $4 x^{3} + x^{2} + 5 x + 8$ are ?

$(x + 1)$ , $(4 x^{2} - 3 x + 8)$

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$(x + 2)$ , $(x^{2} - 3 x + 8)$

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$(x + 3)$ , $(x^{2} + 8 x - 3)$

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$(x + 4)$ , $(4 x^{2} + 3 x - 8)$

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Solution

The correct option is A
$(x + 1)$ , $(4 x^{2} - 3 x + 8)$

The constant term in the given polynomial is 8.

One the zeros of the polynomial can be found by finding the values of given polynomial at the factors of 2
i.e., when x = 1,2,-1 or -2.

$P (- 1) = 4 \times {(- 1)}^{3} + {(- 1)}^{2} + 5 \times (- 1) + 8 = - 4 + 1 - 5 + 8 = 0$

P(-1) = 0, which means that (x+1) is a factor of the polynomial P(x).

The quotient obtained when P(x) is divided by (x+1) is the other factor.

The other factor is $4 x^{2} - 3 x + 8$

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Similar questions

4 x^{3} + x^{2} + 5 x + 8

The factors of the polynomial equation P(x) = $4 x^{3} + x^{2} + 5 x + 8$ is

The factors of the polynomial equation P(x) = $4 x^{3} + x^{2} + 5 x + 8$ are

p (x) = 4 x^{3} + x^{2} + 5 x + 8

p (x)

(x + 2)

(x + 3)

p (x)

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