Question

The factors of the polynomial equation P(x) = $4x^3+x^2+5x+8$ are ?

• A. (x + 1), (4x² – 3x + 8)
• B. (x + 2), (x² – 3x + 8)
• C. (x + 3), (x² + 8x – 3)
• D. (x + 4), (4x² + 3x – 8)

Answer 1

The correct option is A

(x + 1), (4x² – 3x + 8)

The constant term in the given polynomial is 8.

One the zeros of the polynomial can be found by finding the values of given polynomial at the factors of 2
i.e., when x = 1,2,-1 or -2.

$P(-1)=4\times {(-1)}^3+{(-1)}^2+5\times (-1)+8=-4+1-5+8=0$

P(-1) = 0, which means that (x+1) is a factor of the polynomial P(x).

The quotient obtained when P(x) is divided by (x+1) is the other factor.

The other factor is $4x^2-3x+8$