The factors of $x^{2} - x - 12$ are _____

(x + 4), (x + 3)

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(x - 4), (x - 3)

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(x + 2), (x - 6)

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(x + 3), (x - 4)

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Solution

The correct option is D $(x + 3), (x - 4)$
$x^{2} - x - 12$
$= x^{2} - 4 x + 3 x - 12$
$= x (x - 4) + 3 (x - 4)$
$= (x - 4) (x + 3)$
Then, the factors are $(x + 3), (x - 4)$

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