The factors of $x^{2} + x y - 2 x z - 2 y z$ are

(x - y) (x + 2 z)

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(x + y) (x - 2 z)

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(x - y) (x - 2 z)

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(x + y) (x + 2 z)

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Solution

The correct option is A $(x + y) (x - 2 z)$
$x^{2} + x y - 2 x z - 2 y z$
$= x (x + y) - 2 z (x + y)$
$= (x + y) (x - 2 z)$

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Similar questions

⎡ ⎢ ⎣ \begin{matrix} x & x + y & x + y + z 2 x & 3 x + 2 y & 4 x + 3 y + 2 z 3 x & 6 x + 3 y & 10 x + 6 y + 3 z \end{matrix} ⎤ ⎥ ⎦ = 64

x =

$x^{2} - x z + x y - y z = ? (a) (x - y) (x + z) (b) (x - y) (x - z) (c) (x + y) (x - z) (d) (x - y) (z - x)$

∣ ∣ ∣ ∣ ∣ \begin{matrix} y^{3} + 1 & y^{2} z & y^{2} x y z^{2} & z^{3} + 1 & z^{2} x y x^{2} & x^{2} z & x^{3} + 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = 11

(1 - x^{2}) (1 - y^{2}) + 4 x y

Tick (✓) the correct answer:
x² − xz + xy − yz = ?
(a) (x − y)(x + z)
(b) (x − y)(x − z)
(c) (x + y)(x − z)
(d) (x − y)(z − x)

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