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Question

The factors of x31+y3+3xy are


A

(x1+y)(x2+1+y2+x+yxy)

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B

(x+y+1)(x2+y2+1xyxy)

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C

(x1+y)(x21y2+x+y+xy)

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D

3(x+1)(x2+y21)

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Solution

The correct option is A

(x1+y)(x2+1+y2+x+yxy)


x31a+y3+3xy=(x)3+(1)3+(y)33×x×(1)×y=(x1+y)(x2+1y2+x+yxy) =(x1+y)(x2+1+y2+x+yxy)


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