The factors of x3-7 x-6 area xx-6x-1b x2-6x-1c x-1x-2x-3d x-1x-3x-2

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Polynomials

The factors o...

Question

The factors of x³ − 7x + 6 are

(a) x (x − 6) (x − 1)

(b) (x² − 6) (x − 1)

(c) (x + 1) (x + 2) (x + 3)

(d) (x − 1) (x + 3) (x − 2)

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\sqrt{3} x^{2} - 2 x + \frac{1}{2} = 0

x^{2} + \frac{1}{x^{2}} = 5

x - \frac{3}{x} = x^{2}

2 x^{2} - \sqrt{3 x} + 9 = 0

x^{2} - 2 x - \sqrt{x} - 5 = 0

x + \frac{1}{x} = 1

{(x + \frac{1}{x})}^{2} = 3 (x + \frac{1}{x}) + 4

x + \frac{1}{x} = x^{2}, x \neq 0

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\sqrt{2} x^{2} + 7 x + 5 \sqrt{2} = 0

\frac{1}{3} x^{2} + \frac{1}{5} x - 2 = 0

x^{2} - 3 x - \sqrt{x} + 4 = 0

x - \frac{6}{x} = 3

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{(x + 2)}^{3} = x^{3} - 8

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Factorize: $x^{2} + 6 x + 8 = ? (a) (x + 3) (x + 5) (b) (x + 3) (x + 4) (c) (x + 2) (x + 4) (d) (x + 1) (x + 8)$

⎡ ⎢ ⎣ \begin{matrix} X + 2 & X + 6 & X - 1 X + 6 & X - 1 & X + 2 X - 1 & X + 2 & X + 6 \end{matrix} ⎤ ⎥ ⎦ = 0

∣ ∣ ∣ ∣ \begin{matrix} x + 2 x + 6 x - 1 \end{matrix} \begin{matrix} x + 6 x - 1 x + 2 \end{matrix} \begin{matrix} x - 1 x + 2 x + 6 \end{matrix} ∣ ∣ ∣ ∣ = 0

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