The false statement about universal gravitational constant (G) among the following is

Its dimensional formula is

[M^{- 1} L^{3} T^{- 2}]

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It is a vector quantity

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Its value is

6.67 \times 10^{- 11}

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Its unit is N

m^{2} k g^{- 2}

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Solution

The correct option is B It is a vector quantity
G is the universal gravitational constant.
$G = \frac{F r^{2}}{m^{2}}$
Therefore, unit of G is $G = N m^{2} / k g^{2} = [M^{- 1} L^{3} T^{- 2}]$
and its value is $6.67 \times 10^{-} 11$

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Similar questions

6.67 \times 10^{- 11} N m^{2} {k g}^{- 2}

G

6.67 \times 10^{- 11} N - m^{2} k g^{- 2}

6.67 \times 10^{- 11} N m^{2} k g^{- 2}

g^{- 1} c m^{3} s^{- 2}

6.67 \times 10^{- 8}

{c m}^{2} {g m}^{- 2}

G = 6.67 \times 10^{- 11} N - m^{2} / k g^{2}

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