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Byju's Answer
Standard XII
Mathematics
Compound Statement
The false sta...
Question
The false statement among the following is
A
p
∧
(
∼
p
)
is a contradiction
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B
(
p
→
q
)
⇔
(
∼
q
→
∼
p
)
is a contradiction
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C
∼
(
∼
p
)
⇔
p
is a tautology
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D
p
∨
(
∼
p
)
is a tautology
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Solution
The correct option is
B
(
p
→
q
)
⇔
(
∼
q
→
∼
p
)
is a contradiction
(
p
⇒
q
)
⇔
(
∼
q
→
∼
p
)
is tautology as
(
∼
q
→
∼
p
)
is contrapositive of
(
p
⇒
q
)
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4
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