The far point of a myopic person is 80 cm in front of the eye- What is the nature and power of the lens required to correct the problem-A- converging lens of power - 1-25 DB- diverging lens of power -1-25 DC- converging lens of power -1-25 DD- diverging lens of power -1-25 D

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Myopia

The far point...

Question

The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

converging lens of power +1.25 D

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diverging lens of power -1.25 D

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diverging lens of power +1.25 D

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converging lens of power -1.25 D

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Solution

The correct option is B
diverging lens of power -1.25 D

For a myopic person concave lens is used to correct the problem.
Focal length = Distance of far point from eye
Hence, f = -80 cm = -0.8 m.
Power of lens = 1/f = 1/(-0.8) = -1.25 D

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The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?

The correct option is B diverging lens of power -1.25 D For a myopic person concave lens is used to correct the problem. Focal length = Distance of far point from eye Hence, f = -80 cm = -0.8 m. Power of lens = 1/f = 1/(-0.8) = -1.25 D

The correct option is B
diverging lens of power -1.25 D

For a myopic person concave lens is used to correct the problem.
Focal length = Distance of far point from eye
Hence, f = -80 cm = -0.8 m.
Power of lens = 1/f = 1/(-0.8) = -1.25 D