Question

The far point of a myopic persons is $00cm$ in-front of him. What is the power of the lens to correct the problem of his eye?

• A. $-1.0D$
• B. $+1.0D$
• C. $-1.25D$
• D. $+1.25D$

Answer 1

The correct option is A $-1.0D$

Lens should form a virtual image of a distant object at 100cm100cm from the lens. Thus it should be a divergent lens and its focal length=−100cm=−100cm
f=−100cm=−1mf=−100cm=−1m
∴P=1f=1−1=−1D