Question

Question 13
The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages (in year) of the son and the father are respectively
(A) 4 and 24
(B) 5 and 30
(C) 6 and 36
(D) 3 and 24

Answer 1

Let x years be the present age of father and y years be the present age of son.
Four years hence, the relation between the ages is given by the condition
(x + 4) = 4(y + 4)
$\Rightarrow$ x – 4y = 12.....(i)
$\Rightarrow$ x = 6y.....(ii) (Given)
On putting the value of x from Eq. (ii) in Eq. (i), we get
6y – 4y = 12
$\Rightarrow$2y = 12
$\Rightarrow$ y = 6
When y = 6, then x = 36
Hence, present age of father is 36 years and age of son is 6 years.