The feasibility of a chemical reaction can be explained based on ΔH,ΔS and ΔG.
For 2O3(g)→3O2(g), if the reaction is feasible, then:
A
ΔS=+ve
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B
ΔG=+ve
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C
ΔH=−ve
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D
ΔG=−ve
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Solution
The correct options are BΔS=+ve CΔH=−ve DΔG=−ve For the reaction, 2O3→3O2ΔS=+veandΔH=−ve, because moles of gas are increasing and O2 is more stable than O3. And for feasibility of this reaction, ΔG should also be negative.