Question

The feasibility of a chemical reaction can be explained based on $\Delta H,\Delta S$ and $\Delta G$.

For $2O_3\left(g\right)\to 3O_2\left(g\right)$, if the reaction is feasible, then:

• A. $\Delta S=+ve$
• B. $\Delta G=+ve$
• C. $\Delta H=-ve$
• D. $\Delta G=-ve$

Answer 1

Answer: (A), (C), (D)

$\Delta S=+ve$
$\Delta H=-ve$
$\Delta G=-ve$

For the reaction, $2O_3\to 3O_2\Delta S=+veand\Delta H=-ve$, because moles of gas are increasing and $O_2$ is more stable than $O_3$.
And for feasibility of this reaction, $\Delta G$ should also be negative.