Question

The feasible region for an LPP is shown in the given figure. Let z = $3x-4y$ be the objective function. Maximum value of z is



(a) 0
(b) 8
(c) 12
(d) –18

Answer 1

Points	Value of z
B (0, 4)	−16
A (12, 6)	12
O (0, 0)	0

Since z − 3x − 4y
z(0, 4) = 3(0) − 4(4)
= 0 − 16 = −16
z(12, 6) = 3(12) − 4(6)
= 36 − 24
= 12
z(0, 0) = 3(0) − 4(0) = 0
∴ Maximum value of z is 12
Hence, the correct answer is option C.