The feasible region of a LPP is shown in the figure. If Z=5x+2y, then the maximum value of Z occurs at
A
(0,0)
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B
(5,0)
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C
(2,4)
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D
(0,4)
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Solution
The correct option is B(5,0) Extreme PointsZ=5x+2y(0,0)5×0+2×0=0(5,0)5×5+2×0=25(2,4)5×2+2×4=18(0,4)5×0+2×4=8
Maximum value of Z=25 which occurs at (5,0).