The fifth of the H.P., 2,2\(\frac{1}{2}\),3\(\frac{1}{3}\),................. will be
10
Series, 2,212,313,................. are in H.P. ⇒12,25,310,......... will be in A.P.
Now first term a = 12 and common difference d = −110
So, 5th term of the A.P. = 12+(5−1)(−110) = 110
Hence 5th term in H.P. is 10.