The fifth term of an AP is 25 and the ninth term is 37. The common difference of the AP will be ___.
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Solution
5thterm=25 9thterm=37 If the common difference is taken as d , and the first term is taken as a, then a+(5−1)d=25anda+(9−1)d=37 a+4d=25 ------------- (1) a+8d=37 ------------- (2)
Subtracting equation (1) from equation (2), we get 4d=12 ⇒d=3