Question

The Fig. shows the graph of logarithmic reading of pressure and volume for two ideal gases A and B undergoing adiabatic process. From Fig. it can be conclude that :

• A. gas B is diatomic
• B. gas A and B both are diatomic
• C. gas A is monoatomic
• D. gas B is monoatomic and gas A is diatomic

Answer 1

The correct option is D gas B is monoatomic and gas A is diatomic

The figure shows the graph of logarithmic reading of pressure and volume for two ideal gases A and B undergoing adiabatic process. From figure it can be concluded

${\gamma }_B<{\gamma }_A$

and that gas B is monoatomic & gas A is diatomic. The slope of both the gases is negative. The slope for B is much more negative than the slope for A.