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Question

The figure above shows a parallelogram ABCD with AC=3 and AD=5. Calculate the area of parallelogram ABCD.
478827.jpg

A
12
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B
15
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C
18
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D
20
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Solution

The correct option is A 12
ΔABC is congruent to ΔADC, with angles BAC and ACD being of measure 90o
(CD)2+(AC)2=(AD)2
9+(CD)2=25
CD=4
Area of ΔACD=12×AC×CD
=12×3×4
=6, which is also the area of ΔABC
area of parallelogram ABCD=12

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