The figure below is a representation of a simple harmonic progressive wave, progressing in the negative X- axis, at a given instant. The direction of the velocity of the particle at state P in the figure is best represented by the arrow.

\to P A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\to P B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\to P C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\to P D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\to P A$
$v_{p} = - v (\frac{d y}{d x})$
Here v is negative and $\frac{d y}{d x}$ is positive at point P. Hence $v_{p}$ is positive. So P is moving upwards.

Suggest Corrections

Similar questions

Q. The figure below is a representation of a simple harmonic progressive wave, progressing in the negative X- axis, at a given instant. The direction of the velocity of the particle at state P in the figure is best represented by the arrow.

A simple harmonic progressive wave is represented by the equation $y = 8 s i n 2 π (0.1 x - 2 t)$ where x and y are in centimeters and t is in seconds. At any instant the phase difference between two particles separated by 2.0 cm along the x-direction is

Q. A progressive simple harmonic wave is moving in air along the

x

-axis. The part of this wave at a given point

x = x_{0}

from the source and at a certain instant

t = t_{0}

has the waveform shown below in the displacement-time

(y - t)

graph and velocity-time (v-t) graph respectively. Velocity of the wave has value

V_{0}

and its angular frequency is

ω

. Which of the following equations will correctly represent the complete wave at

x = x_{0}

, agreeing with above waveforms?

Q. A simple harmonic progressive wave is given by

y = 0.1 s i n 4 π (50 t - 0.1 x)

in SI system. Find amplitude wavelength, frequency and velocity of the wave.

The equation of a simple harmonic progressive wave is given by
y = 8sin (0.628x – 12.56t)
where x and y are in cm and t is in second.
Find the phase difference in degrees between two particles at a distance of 2.0cm apart at any instant.

Join BYJU'S Learning Program

The figure below is a representation of a simple harmonic progressive wave, progressing in the negative X- axis, at a given instant. The direction of the velocity of the particle at state P in the figure is best represented by the arrow.

The correct option is A →PAvp=−v(dydx) Here v is negative and dydx is positive at point P. Hence vp is positive. So P is moving upwards.

The correct option is A $\to P A$
$v_{p} = - v (\frac{d y}{d x})$
Here v is negative and $\frac{d y}{d x}$ is positive at point P. Hence $v_{p}$ is positive. So P is moving upwards.