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Question

The figure below shows the velocity-time graph for the motion of a bike. Find the displacement of the bike in time interval EF.


A
45 m
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B
35 m
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C
25 m
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D
55 m
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Solution

The correct option is B 35 m
Displacement of the bike in time interval EF = Area under BC.
Area under BC = Area of trapezium EBCF
Area of trapezium EBCF =12(EB+FC)×(EF)
12(25+10)×(53) = 12(35)(2)
35 m
Hence, the displacement of the bike in time interval EF is 35 m.

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