wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The figure below shows the velocity-time graph for the motion of a bike. Find the displacement of the bike in time interval EF.


A
45 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
35 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
25 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
55 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 35 m
Displacement of the bike in time interval EF = Area under BC.
Area under BC = Area of trapezium EBCF
Area of trapezium EBCF =12(EB+FC)×(EF)
12(25+10)×(53) = 12(35)(2)
35 m
Hence, the displacement of the bike in time interval EF is 35 m.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area Under Graph
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon