The figure below shows the velocity-time graph for the motion of a bike. Find the displacement of the bike in time interval EF.
A
45m
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B
35m
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C
25m
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D
55m
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Solution
The correct option is B35m Displacement of the bike in time interval EF = Area under BC. Area under BC = Area of trapezium EBCF ∴ Area of trapezium EBCF=12(EB+FC)×(EF) ⇒12(25+10)×(5−3) = 12(35)(2) ⇒35m Hence, the displacement of the bike in time interval EF is 35m.