Question

The figure denotes a circular lamina of radius 28 cm
The two sectors in the figure are to be cut out find the area of the remaining portion after the two sectors have been cut out.

• A. undefined
• B. undefined
• C. undefined
• D. undefined

Answer 1

Area of the remaining portion = Area of circle - Area of 2 sectors
$=\sqrt{1}(28{)}^2-[\frac{\sqrt{1}(14{)}^2\times 30}{360}\frac{\sqrt{1}(14{)}^2\times 150}{360}+]=\frac{22}{7}\times {28}^2-[\frac{22}{7}\times {14}^2\times \frac{1}{12}+\frac{22}{7}\times {14}^2\times \frac{5}{12}]=22\times 4\times 28-\frac{22}{7}\times {14}^2[\frac{1}{12}+\frac{5}{12}]=88\times 28-22\times 2\times 4\left[\frac{6}{12}\right]=2464-44\times 2\times 4\frac{1}{2}=2464-44\times 7=2464-308=2156c{m}^2$