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Ohm's Law in Scalar Form

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Question

The figure is a part of a closed circuit. Find the currents $i_{1}, i_{2}$ and $i_{3}$ .

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Solution

Given: a part of closed circuit.
To find the currents $i_{1}, i_{2}, i_{3}$
Solution:
By using Kirchhoff's junction rule, we get
At first junction from left side,
$i_{1} + 2 A = 3 A ⟹ i_{1} = 1 A$
At second junction from left side,
$3 A = 1 A + i_{2} ⟹ i_{2} = 2 A$
At third junction from left side,
$i_{2} = i_{3} + 1.5 A ⟹ i_{3} = i_{2} - 1.5 ⟹ i_{3} = 2 - 1.5 ⟹ i_{3} = 0.5 A$
Hence, $i_{1} = 1 A, i_{2} = 2 A, i_{3} = 0.5 A$

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