Question

The figure is a part of a closed circuit. Find the currents $i_1,i_2$ and $i_3$.

Answer 1

Given: a part of closed circuit.

To find the currents $i_1,i_2,i_3$

Solution:

By using Kirchhoff's junction rule, we get

At first junction from left side,

$i_1+2A=3A⟹i_1=1A$

At second junction from left side,

$3A=1A+i_2⟹i_2=2A$

At third junction from left side,

$i_2=i_3+1.5A⟹i_3=i_2-1.5⟹i_3=2-1.5⟹i_3=0.5A$

Hence, $i_1=1A,i_2=2A,i_3=0.5A$