The figure represents a U-tube of uniform cross-section filled with two immiscible liquids- One is water with density - w and the other liquid is of density - The liquid interface lies 2 cm above the base- The relation between - and - wd is-

The correct option is B ρ = ρ _w P_1=P_2 ∴ nbsp; nbsp; P_0+ρ _wgh=P_0+ρ gh ⇒ nbsp; nbsp; ρ =ρ _w ...

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Standard XII

Physics

Streamline Flow

The figure re...

Question

The figure represents a U-tube of uniform cross-section filled with two immiscible liquids. One is water with density $ρ_{w}$ and the other liquid is of density $ρ$ . The liquid interface lies 2 cm above the base. The relation between $ρ$ and $ρ_{w}$ d is:

ρ = ρ_{w}

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ρ = 1.02 ρ_{w}

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ρ = 1.2 ρ_{w}

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None of the above

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Solution

The correct option is B $ρ = ρ_{w}$
$P_{1} = P_{2}$
$∴$ $P_{0} + ρ_{w} g h = P_{0} + ρ g h$
$\Rightarrow$ $ρ = ρ_{w}$

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The figure represents a U-tube of uniform cross-section filled with two immiscible liquids. One is water with density ρw and the other liquid is of density ρ. The liquid interface lies 2 cm above the base. The relation between ρ and ρwd is:

The correct option is B ρ=ρwP1=P2∴ P0+ρwgh=P0+ρgh⇒ ρ=ρw

The figure represents a U-tube of uniform cross-section filled with two immiscible liquids. One is water with density $ρ_{w}$ and the other liquid is of density $ρ$ . The liquid interface lies 2 cm above the base. The relation between $ρ$ and $ρ_{w}$ d is:

The correct option is B $ρ = ρ_{w}$
$P_{1} = P_{2}$
$∴$ $P_{0} + ρ_{w} g h = P_{0} + ρ g h$
$\Rightarrow$ $ρ = ρ_{w}$