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Question

The figure represents four positions of a current carrying loop in a uniform magnetic field directed towards the right. ^n represents the direction of area vector of the loop. The correct order of potential energy is



A
I>II>IV>III
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B
I<III<II<IV
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C
III>II>IV>I
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D
I>III>II>IV
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Solution

The correct option is D I>III>II>IV
Potential energy of a current carrying loop placed in a uniform magnetic field is given by, U=μ.B=μBcosθ
Where, θ is the angle between ^n and B.

Case I : θ=180

UI=μBcos180=μB

Case II : θ=90

UII=μBcos90=0

Case III : θ>90

UIII>0 , But <μB

Case IV : θ<90

UIV<0

So, UI>UIII>UII>UIV

Hence, option (d) is the correct answer.

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