The figure represents two concentric shells of radii $R_{1}$ and $R_{2}$ , and masses $M_{1} a n d M_{2}$ respectively. The gravitational field intensity at the point $A$ at distance a $(R_{1} < a < R_{2})$ is

\frac{G (M_{1} + M_{2})}{a^{2}}

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\frac{G M_{1}}{a^{2}} + \frac{G M_{2}}{R_{2}^{2}}

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\frac{G M_{1}}{a^{2}}

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Solution

The correct option is B $\frac{G M_{1}}{a^{2}}$
From Gauss Law for gravitation, only mass inside the circle with radius a will contribute to the gravitational field. Hence,
$g = \frac{G M_{1}}{a^{2}}$

Answer is option C.

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