The figure shown below depicts the distance travelled by a body as a function of time-The average speed and maximum speed between 0 and 20 s are-A- 1 m - s - 1-6 m - s respectivelyB- 2-0 m - s - 2-6 m - s respectivelyC- 1 m - s - 2-0 m - s respectivelyD- 1-3 m - s - 2-0 m - s respectively

The correct option is C 1 m/s, 2.0 m/s respectively Average speed = 20/20 = 1 m/s Maximum speed is attained between t = 10 s to t = 20 s ∴ Maximum speed = 16/8 ...

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Standard X

Mathematics

Solving a Quadratic Equation by Factorization Method

The figure sh...

Question

The figure shown below depicts the distance travelled by a body as a function of time.

The average speed and maximum speed between 0 and 20 s are:

1 m/s, 2.0 m/s respectively

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1 m/s, 1.6 m/s respectively

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2.0 m/s, 2.6 m/s respectively

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1.3 m/s, 2.0 m/s respectively

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Solution

The correct option is:C
Given Data:
Total Distance, $= 20 m$
Total Time Taken, $= 20 s e c$
$A v e r a g e S p e e d = \frac{T o t a l D i s t a n c e}{T o t a l T i m e T a k e n} = \frac{20 m}{20 s e c} = 1 m s^{- 1}$

Maximum speed:
From figure it is clear that maximum distance, $= 20 m$
Time taken to achieve the maximum distance, between $t = 10 s e c$ to $t = 18 s e c$
And distance covered at this time, $20 m - 4 m = 16 m$
So, $M a x i m u m s p e e d = \frac{M a x i m u m D i s t a n c e}{t i m e i n t e r v a l} = \frac{16 m}{(18 - 10) s e c} = \frac{16 m}{8 s e c} = 2 m s^{- 1}$

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The figure shown below depicts the distance travelled by a body as a function of time. The average speed and maximum speed between 0 and 20 s are:

The figure shown below depicts the distance travelled by a body as a function of time.

The average speed and maximum speed between 0 and 20 s are: