Question

The figure shown is a part of a circuit at steady state. The potential of point P is ______

• A. 1V
• B. 2V
• C. 3V
• D. 4V

Answer 1

The correct option is B 2V

In steady state , capacitors behave like open circuit ( i.e. no current will pass through capacitors).

So $2\Omega$ and $4\Omega$ will be in series, and resultant

resistance $R_1$ will be parallel to $3\Omega$, and new resultant

resistance $R_2$ will be in series with $4\Omega$

Lets call it $R_3$, now applying junction law at point P, $R_3$= $6\Omega$

$\frac{4-p}{2}+\frac{3-p}{1}+\frac{-10-p}{R_3}=0$
we get, $p=2V$