The figure shows a circuit whereC1=C2=C3=C4=4 μF. What is the extra charge flown through the battery when a 12 μF capacitor is introduced between P and Q?
C1=C2=C3=C4
⇒C1C2=C3C4
The given circuit is a balanced Wheatsone Bridge.
Thus, VP=VQ and there will be no flow of current through C5.
So, no extra charge will be flown with the addition of fifth capacitor between P and Q.