The correct options are
B the pressure of the gas is
p0 C tension in the string is zero
D if the gas is heated, the pistons move towards right
Let
p be the pressure of the gas and
F be the tension in the string.
Considering the equilibrium of each piston,
For piston
1:
pA1=p0A1+F⇒p=p0+FA1 ...(Eq 1)
For piston 2:
pA2=p0A2+F p=p0+FA2 ...(Eq 2)
From equations 1 and 2, if
A1≠A2 then the gas may have unique value of pressure only if tension in the string is zero, i.e.,
F=0 .
Thus, pressure of the gas is also atmospheric,
p=p0.
When the gas is heated, its volume increases at constant pressure, therefore, both the pistons shift towards right to accomodate the increased volume of the gas.