wiz-icon
MyQuestionIcon
MyQuestionIcon
9
You visited us 9 times! Enjoying our articles? Unlock Full Access!
Question

The figure shows a meter bridge circuit with AB=100 cm, X=12 Ω and R=18 Ω, and the jockey J is at the balance point. If R is now made 8 Ω, through what distance (in cm) will J have to be moved to obtain a balanced bridge ?


A
20.0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
20
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
20.00
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

In case 1:

X=12 Ω & R=18 Ω

Let the balanced point be at l cm from point A.

AJ=l ; BJ=(100l) cm

Applying balance condition,

XR=l100l

1218=l100l

3l=2002l

l=2005=40 cm

Now in case 2:

X=12 Ω and R=8 Ω

XR=l100l

128=l100l

2l=3003l

l=3005=60 cm

So, Δl=ll=6040=20 cm

Hence, J has to be moved by 20 cm in order to achieve the balanced point.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Wheatstone Bridge
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon