The correct option is B 151.67Ω
From balancing condition of Wheatstone bridge
PQ=RS⇒PR=QS .......(i)
Here, P=65Ω
R=R=?
l1=30cm
l2=100−30=70cm
Also, R=ρlA
In meter bridge, the wire is of uniform cross-section.
So, R∝l
∴QS=l1l2
∴ From Eq. (i)
65R=l1l2=3070=37
∴R=65×73=4553=151.67Ω.