Question

The figure shows a network of currents. The current $i$ will be

• A. $3\text{A}$
• B. $13\text{A}$
• C. $23\text{A}$
• D. $-3\text{A}$

Answer 1

The correct option is C $23\text{A}$


Applying Kirchhoff's first law to junctions $A,B,C\&D$

At $A$,
$i_{AB}=23\text{A}$

At $B$,
$i_{BC}=23+3=26\text{A}$

At $D$,
$i_{CD}=8-5=3\text{A}$

At $C$,
$i_{CD}+i=i_{BC}$

$\Rightarrow 3+i=26$

$\therefore i=23\text{A}$

Hence, option $\left(c\right)$ is correct.