The figure shows a regular pentagon and a regular hexagon put together. How much is ∠ABC? [2 Marks]

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Solution

At point B,
∠ABD + ∠CBD + ∠ABC = 360° [1 Mark]

We know ,
∠ABD = 120° [inner angle of regular hexagon]
∠CBD = 108° [inner angle of regular pentagon]
⇒ ∠ABC = 360° - [120° + 108° ] = 132° [1 Mark]

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